In the book here: http://neuralnetworksanddeeplearning.com/chap3.html
If you scroll down to Exercise 2 in the Softmax Section, it says
Show that $\partial a^L_{j}/\partial z^L_{k}$ is positive if $j=k$ and negative if $j \neq k$. As a consequence, increasing $z^L_j$ is guaranteed to increase the corresponding output activation, $a^L_j$, and will decrease all the other output activations.
Here, $$a_j = \frac{e^{z^L_{j}}}{\sum_{k}{e^{z^L_{k}}}}$$
I managed to prove the part when $j \neq k$ by differentiating as normal to get $$-\frac{e^{z^L_{j}}}{\left(\sum_{k}{e^{z^L_{k}}}\right)^2}$$
which is obviously always negative. However I'm having trouble with when $j=k$. When I differentiated I got an inequality which simplified to proving $$\sum_{k}{e^{z^L_k}}>1$$ I am unsure of how to do this.