Linked Questions

-2
votes
0answers
29 views

Is $\{ww^Ra^{|w|}\mid w\in\{a,b\}^*\}$ context-Free? [duplicate]

How can I prove that this language is context free and construct a pda recognizing it? $L = \{ww^Ra^{|w|}\mid w\in\{a,b\}^*\}$
0
votes
1answer
75 views

Proof that $\{a^ib^jc^k\mid i,j,k\in\mathbb{N}, i<k<j\}$ is not context-free using the Pumping Lemma

$$ L=\{a^ib^jc^k \;| \;i, j, k \in \mathbb{N} \; \text{and} \; i <k<j\} $$ I need to show that this language is not context-free with the help of the Pumping Lemma. My first intuition is, that ...
15
votes
1answer
613 views

Is the language of words that are unbalanced in the first half context-free?

(Practice exam question in computational models) Definition: A word $w\in \{0,1\}^*$ is called balanced if it contains the same number of $0$s as $1$s. Let $L = \{w\in \{0,1\}^*\mid |w|$ is even and ...
1
vote
2answers
474 views

Is a^mb^n where m=n^2 a CFL?

Is $a^mb^n$ where $m=n^2$ a CFL? I have a doubt regrading this problem. Say if we pop $n$ number of $a's$ from the stack for each $b$ then it is a CFL (to be exact DCFL) right? On the other hand I ...
0
votes
1answer
198 views

$L = \{ a^{j!} \mid j \geq1\}$ is not context free by pumping lemma

How I use the pumping lemma to prove that the language $L = \{ a^{j!} \mid j \geq1\}$ is not context-free?
1
vote
1answer
114 views

Acceptance problem for CFGs is not regular

Let $ACFG$ be the language of all encodings $(C,x)$ where $C$ is a context-free grammar that generates a language containing $x$, i.e. $ACFG$ is the acceptance problem for context-free grammars. It is ...
-1
votes
1answer
24 views

Is there any tiny tips to find counter example string for proving some language is not a CFL? [duplicate]

When I prove some language is context free, It is too hard to find example string. Is there any tips? It takes too many time or eventually give up.
1
vote
1answer
39 views

How to prove that a language is not context-free using pumping lemma

I'm trying to prove that that language isn't a context free: $ L = \{ w11w \mid w\in \Sigma^* = \{0,1\}\}$ I succeed to prove that $L = ww$ isn't context free, but not the language above. What ...
0
votes
0answers
20 views

How to prove this language is not context-free language by pumping lemma? [duplicate]

Could I get help to prove that the language $\{a^i b^j c^k \mid i>j>k\ge 0\}$ is not context free language by using pumping lemma?
1
vote
1answer
98 views

Is this language is Context-free language or not?

Is anybody can help me please to determine is this language is Context-free language or not? L={wvw | w,v∈{a,b,c}+} for example: part of the language: acbac, abcab, bbcbb not part of the language:...
1
vote
0answers
12 views

Context free/Non Context free Language [duplicate]

Let L = { uv composed of {0,1} | |u| = |v| and u = v } Do we agree that this language is not a Context Free Language ? If not, why ? Can you give me a pushdown automata that recognizes it or the ...
3
votes
2answers
166 views

Can the pumping lemma for context free languages be extended to any subword?

It is known that in the case of a Regular Language $L$ , the pumping lemma can be extended to apply to any sufficiently long subword of the language, ie, if $uwv \in L$ and $|w| \ge p$ then we can ...
-1
votes
1answer
71 views

How construct PDA to $L = \{x \in(a,b,c,d)^* \mid -10 \leq ( |x|_a + |x|_b) - ( |x|_c + |x|_d) \leq 10 \}$

$L = \{x \in(a,b,c,d)^* \mid -10 \leq ( |x|_a + |x|_b) - ( |x|_c + |x|_d) \leq 10 \}$ I don't have any idea. Can someone help me.
0
votes
1answer
454 views

Prove $ L = \{ww^{R} \in \{a, b\}^{*} : |w|_{a} \equiv |w|_{b} \equiv 0$ $ (mod$ $13) \} $ is regular or context-free or neither

$ L = \{ww^{R} \in \{a, b\}^{*} : |w|_{a} \equiv |w|_{b} \equiv 0$ $ (mod$ $13) \} $ Exercises: If the language L is regular (build a DFA or regular expression) else if the language L is context-...
0
votes
0answers
143 views

Is this language context-free? $\Sigma$ = {a,b,#} L = {x1#x2#...#xk : k$\geq$2, every $x_i \in$ {a,b}* and xi $\neq$ xj for every pair i $\neq$ j} [duplicate]

Is this language context-free? $\Sigma$ = {a,b,#}, L = {x1#x2#...#xk : k$\geq$2, every $x_i \in$ {a,b}* and xi $\neq$ xj for every pair i $\neq$ j} I think it is not, because the PDA can't memorize ...

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