Linked Questions

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72 views

Prove or disprove if L is CFL? [duplicate]

Given $L=\{a^ib^jc^k | i\neq j \space and \space j=k\}$. Is this CFL? How do I write CFG for it or prove it with pumping lemma? Thanks.
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118 views

Is $\{a^mb^nc^{mn}\mid m>n\}$ a context-free language? [duplicate]

Been trying to figure it out for an hour myself and another hour looking around, I cannot find anything with the $c^{mn}$ part. $$L=\{a^mb^nc^{mn}\mid m>n\}$$
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1answer
175 views

Does a pushdown automata exists for the following language?

I have came across a question stating that language $L = a^n b^n c^{2n}$ is not a context free language and hence, no PDA can be constructed for it. But what I am wondering is that, if I add another ...
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1answer
696 views

How to prove that $L = \{a^n b^m a^n b^m \mid n,m \ge 0\}$ is not a CFL?

I'm stuck with the proof. I've tried Ogden's lemma but it doesn't seem to help. The problem is: Let $N$ be the constant of Ogden, let $z = a^N b^{N+1} a^N b^{N+1}$, and $z = uvwxy$. Now I should ...
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0answers
14 views

Non-context free languages with word degree [duplicate]

I have stumbled across these 2 problems $L_1= \{\alpha \mid w \in \{a,b\}^* | \alpha $ has exactly 2 b's$\} $ ,prove that $L =\{ \alpha^n | \alpha ∈ L_1 ,n \ge 0 \}$ is not context free Given : $...
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14 views

How do we determine p (pumping length) in pumping lemma for CFL? [duplicate]

This has been confusing me for a while, how do we exactly choose the pumping length when we want to prove whether a language is CFL or not. For example, when we want to prove that {ww, w: {0,1}* } why ...
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1answer
219 views

Pushdown Automaton for $L = \{ w_1 w_2 : |w_1| =|w_2| , w_1 \neq w_2 \} $

So i know that $L =$ { $ {w_1 w_2 : |w_1| =|w_2| , w_1 \neq w_2} $ } is a CFL, but i cannot make a PDA for it because it doesn't make any sense to me why this is CFL i even know the grammar for it ...
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0answers
82 views

Proof that the language is not regular (Pumping Lemma) [closed]

I have to prove that the following language is not regular: $$\{ x | x = 10^{2n} + 10^n + 1, n ≥ 1\}$$ I am trying to prove it using Pumping Lemma, however, when I expand the expression I have both ...
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10 views

Choose a specific regular language to prove a language is not regular [duplicate]

I've tried a few tricky languages such as D = { w | w has an equal number of occurences of 01 and 10 as substrings} but I don't have the means to prove this one as being not regular (and I cannot ...
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1answer
38 views

Is the language $L = \{a^pb^q \ | \ p \ge 1, \ q \ge 1, \ p \ge q^2 \ or \ q \ge p^2\}$ context free? [duplicate]

Is the language $L = \{a^pb^q \ | \ p \ge 1, \ q \ge 1, \ p \ge q^2 \ or \ q \ge p^2\}$ context free? I should probably use Ogden's lemma, but I don't know how to do that in this case.
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1answer
66 views

Using closure properties to show that $L_1=\{a^lb^mc^m|l,m\ge 0\} \cup L(b^*c^*)$ is regular or not

i'm trying to figure out whether this Union $\left [ L_1=\{a^lb^mc^m|l,m\ge 0\} \cup L(b^*c^*)\right]=K$ is regular or not, now since regular languages are closed under intersection, so i assume $K$ ...
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1answer
172 views

Pumping lemma to show a language is not context free [duplicate]

I have started pumping lemma for context-free grammar by reading Sipser's book and there are two questions right at the end end of the topic which I don't understand how to solve or where to start ...
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1answer
327 views

Pumping lemma with multiple of prime number + a constant

Given the language $$L = \big\{ 0^{m} 1 0^{2m+k} \mid m \text{ prime and } k \ge 1 \big\} $$ show that $L$ is not context free by giving a counterexample of the context free pumping lemma. It may be ...
0
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1answer
40 views

Is the language in the description context free? [closed]

I am stuck on a question. Lets say there is a string that can be created from three alphabets a,b,c the condition is number of a<= number of b<= number of c. I can solve if there are a and b (...
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0answers
173 views

How to show that a language is strictly context sensitive

During a class, we was asked how to prove that a language L is strictly context-sensitive. In particular, we have to prove that $L = \{a^nb^nc^n \mid n > 0\}$ Could you help me to find the ...

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