# Questions tagged [big-o-notation]

Big O Notation is an informal name of the "O(x)" notation used to describe asymptotic behaviour of functions. It is a special case of Landau notation.

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### Understanding of big-O massively improved when I began thinking of orders as sets. How to apply the same approach to big-Theta?

Today I revisited the topic of runtime complexity orders – big-O and big-$\Theta$. I finally fully understood what the formal definition of big-O meant but more importantly I realised that big-O ...
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### Does it make sense to say Big Theta of 1? Or should we just use Big O?

Does saying $f(x) = \Theta(1)$ provide any extra information over saying $f(x) = O(1)$? Intuitively, nothing grows more slowly than a constant, so there should be no extra information in specifying ...
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### Are there variations of the regular runtimes of the Big-O-Notation?

There are multiple $O$-Notations, like $O(n)$ or $O(n^2)$ and so on. I was wondering, if there are variations of those in reality such as $O(2n^2)$ or $O(\log n^2)$, or if those are mathematically ...
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### Asymptotics question

Is $\frac {n!} {2!\cdot 4!\cdot 8!\dots (n/2)!}=O(4^n)$? I am really stuck and I tend to believe it's true, but I don't know how to prove it. Any help would be appreciated!
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### Why $\frac{n^3}{2^{\Omega(\sqrt{\log n})}}$ doesn't refute the lower bound $O(n^{3-\delta})$?

I have a simple quesiton: It is conjectured that All Pairs Shortest Path (APSP) has no $O(n^{3-\delta)}$-time algorithm for any $\delta >0$ by SETH. also there is a result that says APSP can ...
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### Does big-Oh impose an ordered partition on the set of the “usual” functions?

The example in this answer proves the fact familiar to CS students - that the "big-O" is not a total order. However, most algorithm running times analyzed using big-Oh notation are not ...
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### Exact meaning of $2^{\mathcal{O}(f(n))}$

In Sipser's Introduction to the Theory of Computation he uses the notation $2^{\mathcal{O}(f(n))}$ to denote some asymptotic running time. For example he says that the running time of a single-tape ...
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### Asymptotics of $\frac{1}{\log(\frac{2^n}{2^n-1})}$

I am trying to understand the asymptotics of \begin{equation} f(n) = \frac{1}{\log(\frac{2^n}{2^n-1})} \end{equation} In particular, is there some $c \geq 1$ such that $f(n) = O(n^c)$?