Questions tagged [closure-properties]

Questions about operations on objects of some kind that result in objects of the same kind.

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1answer
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Can we say anything about the complement of a regular language?

Given a regular language $L$, can we say anything about its complement $\overline L$? One thing that is trivial to say is that the DFA's for both languages are equal in size as complementing the ...
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1answer
25 views

Using closure properties, prove that $L=\{a^kb^ra^m|k,r,m\ge0 \text{ and } m=k+r\}$ is not regular

I'm trying to prove that $L=\{a^kb^ra^m|k,r,m\ge0 \text{ and } m=k+r\}$ is not regular and, although it's trivial to prove it via pumping lemma, I'm having troubles trying to find a way to prove it ...
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1answer
69 views

Which closure properties are always valid between regular, context-free and non context-free languages?

I am making a scheme that respresents some closure properties (union, intersection, complement and concatenation) for regular languages, context-free languages, decidable languages and RE languages. ...
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1answer
207 views

Have any natural complexity classes been proven not to be closed under complement?

Many important (non-deterministic) complexity classes like NP are believed not to be closed under complement. But have any of them been proven not to be? I'm sure one could construct some contrived ...
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2answers
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Closure of Star-Free Languages under Substitution

Let $L$ be a star-free language over finite alphabet $\Sigma$. A substitution will be a map $\sigma : \Sigma \to \mathcal{P}(\Sigma^*)$. It seems obvious that if $\sigma(a)$ is star-free for every $...
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Prove that the class of regular languages is closed under the Kleene + operation. That is, show that if L is regular, then so is $L^{+}$

This is my attempt at a proof: Let $E$ be a $REGEX$ accepting $L$. We claim the $REGEX$ $E^{'} = E^{+}$ accepts L. i.e. $L(E^{+}) = (L(E))^{+}$ $L^{+}$ is regular since there is a $REGEX$ $E^{+}$ ...
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1answer
27 views

How do i prove this language is regular? [duplicate]

I have this language {0+1+0+} and i need to prove it is regular,i had the idea to use the closure properties but i can find any regular languages to unify perhaps.Any ideas?
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21 views

Relationship between Kleene Star of a subset of regular language and the regular language

If $L(R_1) \subseteq L(R_2) \subseteq L(R_3)$ then $L(R_1)^* \subseteq L(R_2)^* \subseteq L(R_3)^*$. Does this also imply that $L(R_1)^* \subseteq L(R_3)$?
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1answer
279 views

Closure of regular languages under deleting a 1 from each even run of 1s

Let $R$ be a regular set over the alphabet $\{0, 1\}$. Give a machine construction to prove that the set obtained by deleting one 1 from each even length block of 1’s is also regular, and using ...
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1answer
33 views

Regularity of a language constructed from a know regular language

I'm working through so textbook questions on regular languages, and came across a problem that amounts to showing the following language is regular, given that $A$ is a regular language: $$ \{x|\...
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1answer
51 views

PDA kleene star construction

I know how to prove that CFL are closed under kleene star operation using CFG. I can't find online or in class notes a proof using PDA. I would appreciate description of the basic idea (not formal).
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3answers
8k views

Is every subset of a decidable set, also decidable?

Is it true that if A is a subset of B, and B is decidable, than A is guaranteed to be decidable? I believe it would be true because all the subsets of B should also be decidable making A decidable. I'...
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0answers
49 views

How to show that language L is NOT context-free?

True or false: To show that a language L is not context-free, one can alternatively show that the union between L and a known context-free language is not context-free. I know that you can prove ...
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1answer
24 views

closure of Context free grammer to homomorphism using PDA

I was looking online, on sipser book, and on lecture notes and I can't find a proof to closure of context free languages to homomorphism that using PDA instead of CFG. I'm not looking for a full and ...
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1answer
53 views

Complement of $0^n1^n | n \in \mathbb{N}$

I know why A is irregular by Closure properties of irregular language. I also know the complement of $ \{ 0^n 1^n | n \in \mathbb{N}\}$ is $A = \{ 0^i 1^j| i \neq j\} \cup (0 \cup1)^*(1)(0 \cup1)^*0(0 ...
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1answer
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Decidability of a language and inclusion between two other languages

I have this assignement that asks to say if the following statement is true or false, and possibly justifying the answer: "Let L₁, L₂ be decidable languages. For every language L s.t. L₁ ⊆ L ⊆ L₂, L ...
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1answer
97 views

Zigzag concatenation of two languages

Given two regular languages $A,B$ on the same alphabet $\Sigma$, I want to show that the following language is regular: $$ \{a_1b_1 \ldots a_kb_k \in \Sigma^* \mid a_1,\ldots,a_k,b_1,\ldots,b_k \in \...
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1answer
27 views

How to define an automata for zig zag concatenation? [duplicate]

I have two DFAs one for language A and one for language B. I'm asked to make an FDA that is the zig-zag concatenation of letters of A and letters of B. This is described by the following: {w: w = $a_1 ...
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1answer
138 views

Strings of infinite length?

Suddenly a thought came to my mind and I thought of resolving it as follows. We know that: String is a finite sequence of symbols from an alphabet $\Sigma$ i.e. we cannot have an infinite sequence ...
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3answers
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$\mathcal{G} = \{ v_2 v_4 \ldots v_{k} : v_1 v_2 v_3 v_4 \ldots v_{k-1} v_{k} \in \mathcal{L}, \text{ $k$ even} \} $ is context free language

Let $\mathcal{L}$ be context free language over alphabet $\Sigma$. Define $\mathcal{G}$ as $$\mathcal{G} = \{ v_2 v_4 \ldots v_{k} : v_1 v_2 v_3 v_4 \ldots v_{k-1} v_{k} \in \mathcal{L}, \text{ $k$ ...
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0answers
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$L = \{\alpha^i \beta^j \gamma^k \vert i,j,k \in \mathbb{N}_0, (i=1) \Rightarrow (j=k)\}$

I am asking this question here, because I am not allowed to comment on the thread that I am actually interested in, but maybe someone can still help me? I alredy found an anwser to the Problem above (...
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Decidability of equality of expressions involving exponentiation

Let's have expressions that are finite-sized trees, with elements of $\mathbb N$ as leaf nodes and the operations {$+,\times,-,/$, ^} with their usual semantics as the internal nodes, with the special ...
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Why DCFL is not closed under kleene star?

I have read somewhere that DCFL is not closed under kleene star. but I haven't found any example
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2answers
147 views

Why L' is not regular?

$$L'=\{ww|w\in L\}$$ I need to give an example of regular language L for which the concatenation of 2's $w$ gives $L'$ which is not regular. How can I give such an example if according to closure ...
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1answer
346 views

If $L$ is a regular language then so is $L/a =\{w | wa ∈ L\}$, where $L$ is a language over $\Sigma$ and $a \in \Sigma$

I'm trying to work out a proof by construction that $L/a$ would be regular. $a$ is any final symbol at the end of an accepted string, so I figured the only part of the machine that would have to be ...
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Myhill-Nerode and closure properties

It is well known that regular languages are characterized by the Myhill-Nerode equivalence. For language $L$ over $\Sigma^*$ define the equivalence $x\sim_L y$ over $\Sigma^*$ iff for all $z\in\Sigma^*...
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3answers
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Why are DCFL not closed under concatenation or Union whereas CFL is?

I understand that DCFL they are not closed under concatenation or Union. As without non determinism, PDA cannot decide when to jump to the next one in case of concatenation and without epsilon moves ...
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3answers
257 views

Show that if A is regular, then the subset containing only even language strings, is also regular

A language A, even(A) is the subset of A consisting of those strings in A of even length: even(A) = { x∈A | |x| is even} I need to use closure properties show ...
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2answers
161 views

If L is a regular language then the language replace(L,σ,τ) is also regular

I am stuck at the following problem: Prove that if $L$ is a regular language over some alphabet $\Sigma$ and that $\sigma, \tau \in \Sigma$, Then the language $replace(L,\sigma,\tau)$ is regular. ...
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1answer
28 views

Policies for handling symbols leaking out of a lexical scope

Suppose it's possible for a symbol to escape the scope in which it is defined. What are considered the possible policies for handling that? I mean possible in the sense of what choices of language ...
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3answers
2k views

Are regular and context free languages closed against making them prefix-free?

For a language L we define: $\qquad A(L) = \{ x \in L \mid \text{ no proper prefix of x is in L} \} $ Are regular / context free languages closed under this operation ? For regular languages I ...
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1answer
236 views

Prove/disprove: If $𝐿_1$ is a finite language but not empty and $𝐿_2$ is NOT regular then $𝐿_1 \circ 𝐿_2$ is NOT regular

That what I have so far, but I am not sure at all. Assume toward contradiction that $𝐿_1 \circ 𝐿_2$ is regular. Define $\Sigma' = \{\sigma'|\sigma\in\Sigma\} $. Define a regular substitution $\...
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2answers
190 views

Is the difference of two context-free languages still context-free?

i am asking myself the following question: Assuming: A and B are context-free languages, then A - B (difference) must also be context-free language, right? but I do not know how to prove it.
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1answer
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Quotient of languages, regular quotient and their closedness

Left quotient is defined as below at this link: Left quotient of $L1$ by $L2$: $L1\backslash L2:= \{u\in \Sigma^*|vu\in L1$ for some $v\in L2 \}$ Wikipedia defines it as follows: $L_1\backslash L_2=...
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3answers
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Show that P is closed against the Kleene star

I have that question that looks kinda easy at first but it is quite hard. Let $L\in P$. Prove that $L^*\in P$ my approach: I tried to generate a Turing machine but I got stuck with the thing of ...
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3answers
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Closure of CFL against right-quotient with regular languages

Let $A/B$ = $\{ w \mid wx \in A$ for some $x \in B \}$. Show that if A is context free and B is regular, then $A/B$ is context free. My interpretation of this is is that we need to show that if a ...
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1answer
68 views

Are models of computation closed under composition?

It's common to ask whether a particular class of languages $\mathcal{C} \subseteq \mathcal{P}(\Sigma^*)$, for some alphabet $\Sigma$, is closed under complement, or union, or intersection, or ...
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Is $A$ regular if $A^{2}$ is regular?

If $A^2$ is regular, does it follow that $A$ is regular? My attempt on a proof: Yes, for contradiction assume that $A$ is not regular. Then $A^2 = A \cdot A$. Since concatenation of two non-regular ...
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4answers
416 views

What happens with trios, full trio, (full) semi-AFL, (full) AFL if we require closure under intersection?

Wikipedia says: A trio is a family of languages closed under e-free homomorphism, inverse homomorphism, and intersection with regular language. A full trio, also called a cone, is a trio ...
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1answer
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Difference between substitution, morphism, and homomorphism

In closure properties, I got confused between substitution and morphism. 1) According to Wikipedia, string substitution means to map letters in a set of alphabets to languages (possibly in a ...
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1answer
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How can the union of two 'context-free but not regular' languages be regular?

I cannot understand how the union of two languages which are context-free but not regular, can result in a regular language: If $L_1$ and $L_2$ are 'context-free but not regular' languages, defined ...
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1answer
674 views

Complexity classes that are closed under subtraction

Are NP or P closed under subtraction? Im having a hard time deciding whether they are or aren't. Question was edited Original question: Im having some hard time figuring out what languages are closed ...
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Intersection of decision problems?

Say we have two problems $\Pi_1\in NP$ and $\Pi_2\in coNP$. Where does $\Pi_1\cap\Pi_2$ live?
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2answers
120 views

Can the regular image of a context-free language be undecidable?

I just need to know the truth or falsity of a simple statement. Let $L_1$ be a context-free language over an alphabet which contains some number of characters $\Sigma$, as well as a single, special ...
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1answer
29 views

Getting from one language to the other using closure properties(automata) [duplicate]

I am trying to deduct how i can, using closure properties, deduct that since the following language is not context free $$L=\left\{abc^{i_1}bc^{i_2}...bc^{i_{2m}}def^{j_1}ef^{j_2}..ef^{j_{2n}}ghq^{k_1}...
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2answers
103 views

DSPACE(f(n)) closed under complement

I think you can create the complementary language that is an element of DSPACE($f(n)$), where $f(n) \geq \log(n)$ by adding a step to the algorithm that reverses the answer. By that the function $f(n)$...
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4answers
16k views

Union of regular languages that is not regular

I've come across that question : "Give examples of two regular languages which their union doesn't output a regular language. " This is pretty shocking to me because I believe that regular languages ...
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3answers
257 views

First half of context-free palindromes

If $L\subseteq\Sigma^*$ is a regular language, then $\text{mir}(L) = \{ww^R \mid w\in L\}$ is context-free. This is a nice exercise. Question: does the reverse hold? Thus, if $\text{mir}(L)$ is ...
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2answers
476 views

Proving that L is not regular using closure properties

I need to show that the following language is not regular. $$L = \{\ ab^jc^j\ |\ j \geq 0\ \}\ \cup\ \{\ a^ib^jc^k\ |\ i, j, k \geq 0 \ and\ i \neq 1\ \}$$ There is also a hint that it cannot be ...
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3answers
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What is complement of Context-free languages?

I need to know what class of CFL is closed under i.e. what set is complement of CFL. I know CFL is not closed under complement, and I know that P is closed under complement. Since CFL $\subsetneq$ P I ...

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