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Defining decision-problem complexity classes by counting branches of a polynomial-time NTM

This answer on another SE community discusses the concept of a "counting complexity class". As far as I can tell, the author is using that term in a slightly nonstandard way: most sources (PS format) ...
2
votes
1answer
60 views

On lowness of $\oplus P$

$\oplus P$ is low for itself ($\oplus P^{\oplus P}=\oplus P$). Are there other complexity classes $\mathcal D$ that satisfy $\mathcal D^{\oplus P}=\oplus P$? Are there complexity classes $\mathcal C$ ...
3
votes
1answer
378 views

Proof of $P^{\text{#}P} = P^{PP}$

I was reading this article on the complexity class $PP$. In the fourth paragraph there is a claim that $P^{\text{#}P} = P^{PP}$ and that it can be proved using binary search. Can anyone please ...
11
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2answers
148 views

Does #$P$-Completeness imply approximation hardness?

Let $\Pi$ be some counting problem which is known to be #$P$-Complete. Does it imply that $\Pi$ is $APX$-hard (i.e. no PTAS for the problem exists unless $P=NP$)?