Questions tagged [landau-notation]

Questions about asymptotic notations such as Big-O, Omega, etc.

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Is $n^{1.03} = \Omega(n \log \log n)$?

We had this problem on our Algorithms final. It threw me off because if $\log$ is $\log_2$ then graphing the function shows this is not true, but if $\log$ is $\log_{10}$ then it looks like it is. How ...
pod's user avatar
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Upper bounding this expression

I need to prove that the following expression is $\mathcal O(n \log n)$ with the substitution method: $$ T(n) \leq 3\log n + n + \frac{6}{n}\sum^{n - \frac{\log n}{3}}_{i=\frac{\log n}{3}} T(i)$$ This ...
joeren1020's user avatar
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Proving an asymptotic bound with induction

Suppose we want to prove by induction that $f(n) \in \Theta(g(n))$. How should the induction proof be set up? I'm tempted to say that the base case should prove that $f(1) \in \Theta(g(1))$ and the ...
Keio203's user avatar
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Is $n=\Theta(n^{1+o(1)})$?

Is $n=\Theta(n^{1+o(1)})$? To me it appears to be true as $n$ tends to infinity $n^{o(1)} =0$.
Shi's user avatar
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Finding the constants in Landau notation

I am trying to find the constants $n_0$ and $c$ to show that some given functions belong to the $O(\cdot)$ equivalence class. But, while it seems easy, I am not sure whether I am allowed to do what I ...
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Trying to understand the basic about recurrence trees

I have little background on recurrence trees, and I am working on the following exercise: Exercise. Take $T(n) = 2T(n/2) + 3\log(n)$. Draw the recurrence trees for $n=2$ and $n=4$. What can we ...
Rodrigo's user avatar
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Linearity property of summation applied to Big Theta notation (CLRS math background appendix)

Section A.1 of the Mathematical Appendix of the CLRS, the third edition, page 1146, contains the following formula stating linearity property of summation applied to $\Theta$ notation: $$ \sum_{k=1}^{...
Pavlo Maistrenko's user avatar
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Shifted Big Os. How to say O((n+c)!) = O(n!)?

Suppose an algorithm is $O(n!)$, but we need to run it $n$ times, so the total complexity is $nO(n!) = O(n \cdot n!) = O((n+1)! - n!) = O((n+1)!)$ Strictly, there is no constant factor that would make ...
TrayMan's user avatar
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Prove that $ln(n)^r \in o(n^p)$ for $p>0$ and $r\in \mathbb{R}$

I am trying to proof $f\in o(g)$ Let be $r,p\in \mathbb{R}$ with $p>0$ We have $f(n)=ln^r (n)$ and $g(n)=n^p$ I have already proofed that $ln(n)\in o(n)$ via l'Hospital $\lim\limits_{n\to \infty}\...
Florian Bauer's user avatar
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Equivalene of big O definitions (Limit Definition $\Longleftrightarrow$ Quantifier Definition)

I need to proof, that both definitions of the Big 0 notation are equiavlent, but I am not sure if my proof works both ways of the equivalence. Definitions: Let f,g be functions. $f(n)\in \mathcal{O}(...
Florian Bauer's user avatar
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Does a function $f$ exists such that: $f(n-k) \ne \Theta(f(n))$ for some constant $k\geq1$?

I have encountered the following question in my homework assignment in Data Structures course: "Does a function $f$ exists such that: $f(n-k) \ne \Theta(f(n))$ for some constant $k\geq1$ ?" ...
Hartman's user avatar
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Why is $\sum_{i=0}^n\sqrt{i}\log_2^2i \geq \Omega(n\sqrt{n}\log_2n)$?

Where $\Omega(f)$ denotes the set of functions with f as lower bound, why is $\sum_{i=0}^n\sqrt{i}\log_2^2i \geq \Omega(n\sqrt{n}\log_2n)$? How can the function on the left be compared to a whole set?...
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Show that $O(\text{max}\{f(n),g(n)\})=O(f(n)+g(n))$

Show that $O(\text{max}\{f(n),g(n)\})=O(f(n)+g(n))$ Can I keep the same constant $c$ in each of the cases? Consider two cases: $$1)f(n)>g(n);O(\text{max}\{f(n),g(n)\})⇒O(f(n))\Rightarrow d(n) ≤c⋅...
Elliott de Launay's user avatar
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How do I prove that $3x^3 +2x + 1 $ is $\omega(x \cdot \log x) $

I am trying to answer this question: $3x^3 +2x + 1$ is $ \omega(x \cdot \log x)$ My question is how to solve this question. Here is what I have tried so far: I applied the definition $3x^3 + 2x + 1 ...
Jeffrey K.A's user avatar
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3 answers
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Prove little o with just the definition

I have been searching for a while now but couldn't find anything about this exact pair of functions with the little $\mathcal{o}$ notation. Given the functions $f(n) = 2^{n}$ and $g(n) = n!$ I am ...
Ferdan's user avatar
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O nation prove with limit theroem? [duplicate]

I'm working on my school homework,even though i found all three of these. It says use limit to compare. I confused , what should i do, i mean its obvious C A B
Fatih Can's user avatar
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Big O Tires Question? [duplicate]

My question is regarding the last paragraph of this excerpt from "Cracking the Coding Interview." (For some reason, my table is not formatting here.) What's the runtime of this code? ...
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How to tackle Big O proofs that involve multiple parameters

I am getting more and more familiar with the whole concept of time complexity but I have never encountered an example where more than one parameter is involved. Therefore, is it possible(well, I am ...
priortt's user avatar
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Asymptotic growth of a function containing a sum

How to compare the asymptotic growth of a function containing a sum with another function? I'm not sure how I'm supposed to dissolve the sum. Usually I just take the limis of f(x)/g(x). If that fails ...
Paul Erlenmeyer's user avatar
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Is this a correct way to thing about asymptotic notations?

I am reading a book on algorithms. It says that $2n^2+3n+1=2n+\Theta(n)$. For a person like me who has studied some set theory but not from axioms, this notation seems a bit insane. I was wondering ...
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2 votes
2 answers
705 views

Induction proofs in Big-O notation

I'm not sure how go about this question: Prove the following inequality. For a correct proof, we require a value of the constant $c>0$ and an $n \in \mathbb N$, such that $\forall n>N : f(x)<...
YamahaJacoby's user avatar
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1 answer
90 views

How do I simplify $O\left({n^2}/{\log{\frac{n(n+1)}{2}}}\right)$

I'm not very certain about how to deal with asymptotics when they are in the denominator. For $$O\left(\frac{n^2}{\log{\frac{n(n+1)}{2}}}\right)$$, my intuition tells me that it should be treated in a ...
David's user avatar
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14 votes
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Is O((n^2)*log(n)) greater than O(n^(2.5))?

I know that $O(n^2\times \log(n))$ is greater than $O(n^2)$, but is $O(n^2\times \log(n))$ greater than $O(n^{2.5})$?
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2 answers
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Summation of asymptotic notation

How can we solve summation of asymptotic notations like given below: $$ \sum_{k=1}^{n-1} O(n). $$
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2 votes
1 answer
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When are log complexities considered equivalent?

Would we consider $O(\log_2(n))$ to be the same complexity as $O(\log_2(n-1))$? Why or why not? I'm specifically wondering about how the number we take the log of affects the time complexity.
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Why is $\sum_{i=1}^n O(i)$ not the same as $O(1)+O(2)+\dots+O(n)$?

The well-known textbook Introduction to Algorithms ("CLRS", 3rd edition, chapter 3.1) claims the following: $$ \sum_{i=1}^n O(i) $$ is not the same as (I'm not using DNE because the book explicitly ...
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1 answer
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Substitution for Landau's O notation formula

I found the following description when I was reading a paper on computational complexity theory. This can be done ... in time 2n・poly(logs,n)+2O(logs)c. For s≤2no(1), the runtime is 2n・poly(n). I ...
NEUTRON's user avatar
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which rule can conduct this formula $\log n = O(n^{0.000001})$? [duplicate]

i am learning this post about Big O, which gives this formula $$\log n = O(n^{0.000001})$$ why is that?
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Run time of pseudo code in big theta notation [duplicate]

I am looking for the run time of the following pseudo code. ...
gamma's user avatar
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3 answers
357 views

How can i prove this asymptotic comparison? [duplicate]

This is an exercise that's part of my assignment, but it is optional and flagged as a "challenge". I would like to discuss its solution: Prove that: $$ 27\log{n} + \sqrt{n} = \theta(\sqrt{n})$$ ...
heresthebuzz's user avatar
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3 answers
100 views

If my algorithm has complexity O(n!*n), can I just write O(n!), or do I have to keep it like O(n!*n)?

Just as I asked in the title: if my algorithm has complexity $O(n!\times n)$, can I just write $O(n!)$, or I have to keep it like $O(n!\times n)$?
ellamenopee's user avatar
2 votes
1 answer
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Proving Big Omega of a polynomial without limits

Here is the definition of $\Omega$: $f(n) = Ω(g(n))$ iff there exist positive constants $c$ and $n_0$ such that $f(n) \ge cg(n)$ for all $n\ge n_0$. Here is one theorem: If $f(n) = a_m n^m + \...
js lee's user avatar
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2 answers
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What is wrong with this solution for $\mathcal{O}({\log({n \choose \frac{n}{2}})})$?

In this recitation on MIT OCW, the instructor uses Stirling's approximation to calculate that $\mathcal{O}({\log({n \choose \frac{n}{2}})}) = \mathcal{O}(n)$. However, I went through the following ...
ubadub's user avatar
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1 answer
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Asymptotic relation between n! and (n+1)!

I am having difficulty writing this formally. I know that by L'Hospital's rule we can reduce it to $\lim_{n \to \infty} \frac{n+1}{n}$ which is a constant and hence $n = \theta (n+1)!$. But I am not ...
johanso's user avatar
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1 answer
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Are the following Big Oh Notations equivalent?

In the context of Upper bounds computaion and Big Oh Notation, I was wondering if the following could be proved... if they are equivalent. $\mathcal{O}((log(n))^{-1}) = (\mathcal{O}(log(n)))^{-1}$ $\...
GermanShepherd's user avatar
48 votes
10 answers
11k views

O(·) is not a function, so how can a function be equal to it?

I totally understand what big $O$ notation means. My issue is when we say $T(n)=O(f(n))$ , where $T(n)$ is running time of an algorithm on input of size $n$. I understand semantics of it. But $T(n)$ ...
doubleE's user avatar
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How come O(n) + O(logn) = O(logn)

How come O(n) + O(logn) = O(logn)? When talking for example about an algorithm that has two operations. One of them takes O(n) and the other O(logn) and in the end we say that the total complexity is ...
ponikoli's user avatar
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1 answer
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Is this a valid use of big-O notation?

Suppose that $m=O(n^{c+1/2})$ for some real $c>0$ and $x=O(\sqrt{\log m})$. Are the following two computations valid? I understand that I'm abusing notations a bit to get at the desired results. ...
stats134711's user avatar
1 vote
1 answer
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Introductory explanation of the Big-Oh properties

I've noticed that Big-Oh notation actually has some properties such as summation, product but i couldn't find an introductory explanation for their use or how they can help to solve asymptotic ...
heresthebuzz's user avatar
1 vote
2 answers
194 views

How to prove $\Theta(g(n))\cup o(g(n))\ne O(g(n))$

How to prove $\Theta(g(n))\cup o(g(n))\ne O(g(n))$ ? Is there a simple example for understanding? Seems there's a gap between $O(g(n))- \Theta(g(n))$ and $o(g(n))$ just from the definition. But I ...
FlowerSun's user avatar
1 vote
1 answer
35 views

Is this correct in term of big-oh notation: given $g = O(f)$ and $h = O(f)$ can we say $g = O(h)$?

We have two equations $g = O(f)$ and $h = O(f)$ , then can we derive that $g = O(h)$. I came up with following proof but i dont know it's correct or not. $$g = O(f)$$ $$g \le c_1*f $$ $$h \le c_2*f $$ ...
user4828815's user avatar
1 vote
1 answer
152 views

Asymptotic Notation Analysis

2^n=O(3^n) : This is true or it is false if n>=0 or if n>=1 since 2^n may or not be element of O(3^n) I need a hint to figure the problem
geometry18's user avatar
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1 answer
515 views

complexity class of functions [duplicate]

What would these statements mean if f(n) and g(n) are functions over natural numbers? g(n) is in Θ(f(n)). and An algorithm is in the complexity class Θ(f(n)).
wick123's user avatar
1 vote
3 answers
934 views

What is the constant $C$ in the definition of asymptotic notations?

For example in the definition of $\Theta$: $f(n) = \Theta(g(n)$ if there exist positive constants $c_1, c_2$ and $n_0$ such that $$ 0 \leq c_1 \cdot g(n) \leq f(n) \leq c_2 \cdot g(n) \text{ for ...
John Sall's user avatar
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1 answer
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How can I find $\Theta(log(m_1)+...+log(m_k))$ as related to $m$?

given: $$m_1+m_2+...+m_k=m$$ How can I find $\Theta(log(m_1)+...+log(m_k))$ as related to $m$? I know that i can doing that: $O(log(m_1)+...log(m_k))=O(log(m)+...+log(m))=O(k \cdot log(m))$ , but ...
WantToKnowMath's user avatar
2 votes
1 answer
71 views

Complexity Reduction Analysis

I am struggling to grasp fully grasp complexity reductions, I have this example that I am working through and can not fully comprehend how to determine the complexity of one algorithm given the ...
moose0306's user avatar
0 votes
2 answers
237 views

Two questions about complexity class

Does $2^{n-1}$ and $2^{n}$ share the same complexity complexity class as exponential named as $O(2^n)$? So the former belongs to $O(2^n)$ even though it's one order lower? What is the name of the ...
Ka Wa Yip's user avatar
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3 votes
1 answer
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Is $T(n) = Ω (n^2)$ the same as $n^2=O(T(n))$?

Question: In the problem below, does proving $T(n) = O(n^2)$ and $n^2 = O(T(n))$ lead to the same result as proving $T(n)=O(n^2)$ and $T(n)=Ω (n^2)$? Which would be the better approach to take? I feel ...
Lucky's user avatar
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If $f(n)=\omega(h(n))$ and $g(n)=o(h(n))$ then is $f(n)=\Theta(g(n))$?

My question is exactly what the title says. If I have that $f(n)=\omega(h(n))$ and $g(n)=o(h(n))$ hold, then does $f(n)=\Theta(g(n))$ hold as well? My intuition says that the second part is false, but ...
LionsWrath's user avatar
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1 answer
664 views

Big O understanding given different input sizes

I have a question about big O notation. Let's say I have 3 algorithms which, for an input of size $n$, have time complexity $O(n)$, $O(n^2)$ and $O(n \log n)$, respectively. Assume that all 3 ...
user86002's user avatar

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