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Questions tagged [pumping-lemma]

Necessary properties of formal langagues in certain classes that rely on closure against repetition of certain subwords. Make sure your question isn't covered by applying the techniques in https://cs.stackexchange.com/q/1031/755.

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Proving non-regularity of $\{a^p \mid p \in \text{Prime} \}$ without pumping lemma

I was wondering whether it is possible to prove $\{a^p \mid p \in \text{Prime} \}$ is a non-regular language without using the pumping lemma. I'm having trouble choosing an alphabet that completes the ...
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1answer
36 views

Is this language L context-free?

The language $$L = \{x^r \# y | x, y \in \{a, b, c\}^*\\ \text{ and }x\text{ is a contiguous sub-string of }y\}$$ where $x ^ r$ denotes the backward written word x, is context-free. Can someone ...
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1answer
27 views

Pumping lemma for regular languages

I have a vey specific question regarding the pumping lemma in the context of regular languages. The theorem states that if $L$ is a regular language, then there exists a constant $n$ such that for ...
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2answers
34 views

Can the pumping lemma for context free languages be extended to any subword?

It is known that in the case of a Regular Language $L$ , the pumping lemma can be extended to apply to any sufficiently long subword of the language, ie, if $uwv \in L$ and $|w| \ge p$ then we can ...
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1answer
68 views

Which word could I use for the Pumping Lemma proof?

I have the language $ A_{1} \triangleq\left\{a w c^{l} d^{m}\mid l \in \mathbb{N} \wedge m \in \mathbb{N}^{+} \wedge w \in\{a, b\}^{*} \wedge |\left.w\right|_{a}=l+m\right\} \operatorname{with} \...
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1answer
39 views

Pumping Lemma vs Myhill-Nerode [duplicate]

I was searching for a difference on both ways of proving that a language is not regular but I didn't came up with much. Let us take the following as an example: $$ L = \{ a^n b^n \mid n \ge 0\} $$ ...
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41 views

Show that the language L = {www : w ∈ {0, 1} ∗} is not regular [duplicate]

Hey was wondering if I'm applying the pumping lemma correctly for this proof or if this proof could be improved? Suppose $L = \{www:w\in\{0,1\}^*\}$ is a regular language. Let $p$ be the number from ...
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1answer
35 views

Pumping Lemma on Language with subtracted length

My study group and I have had some back and forth on one exercise and I haven't found any matching solution online. The task looks as follows: Prove that $L$ is not regular given $$ L = \{ a^k b a^{m-...
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1answer
47 views

Is complement $L = \{ w : |w|_{a} \equiv |w|_{b} \vee |w|_{c} \equiv |w|_{d} \}$ context-free

$L = \{ w : |w|_{a} \equiv |w|_{b} \vee |w|_{c} \equiv |w|_{d} \}$ In my opinion complement of the L language is $L^{C} = \{ w : |w|_{a} \neq |w|_{b} \wedge |w|_{c} \neq |w|_{d} \}$ I choose to ...
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1answer
51 views

Prove $ L = \{ww^{R} \in \{a, b\}^{*} : |w|_{a} \equiv |w|_{b} \equiv 0$ $ (mod$ $13) \} $ is regular or context-free or neither

$ L = \{ww^{R} \in \{a, b\}^{*} : |w|_{a} \equiv |w|_{b} \equiv 0$ $ (mod$ $13) \} $ Exercises: If the language L is regular (build a DFA or regular expression) else if the language L is context-...
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2answers
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Is the language of words that contain a square regular or context-free? [duplicate]

$ L = \{w \in\{a,b\}^{*} : \exists_{x,y,z} , w=xyyz \wedge y \neq \epsilon \}$ I have a problem with this exercise. I need to determine if this language is regular, context-free or not both and ...
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1answer
70 views

Is Language $ L = \{ww^{R} \in \{a,b,c\}^{*} : |w|_{a} \not\equiv |w|_{b} $ and $ |w|_{b} \not\equiv |w|_{c} \} $ context free?

$ L = \{ww^{R} \in \{a,b,c\}^{*} : |w|_{a} \not\equiv |w|_{b} $ and $ |w|_{b} \not\equiv |w|_{c} \} $ I would use the Ogden pumping lemma. Assumption $n < m$ where $n$ is a number from lemma. My ...
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1answer
112 views

Find the Pumping Length for Language L of (2+3k) a's or (10+12k) b's

The following question on the theory of computation is GATE 2019 CS question 24: For $Σ = \{a, b\}$, let us consider the regular language: $$L = \{x \mid x = a^{2+3k} \text{ or } x = b^{10+12k}, k ...
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2answers
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Pumping Lemma. Why is there a word w in L for infinite languages with n≤|w|≤2n

The following comment on an other question says that if we have an infinite language L that satisfies the pumping lemma for regular languages then we have a word with n≤|w|≤2n which is in L. (n is the ...
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1answer
52 views

How to choose a word to apply the Pumping Lemma?

I have some questions about the PUMPING LEMMA. First of all, I do not study computer science, I still go to school, but I'm very interested, so I could make mistakes. And sorry about my English :) ...
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1answer
68 views

Which word could I use for the pumping lemma?

I have a problem to start my proof because I do not find a word $w$ where I can use the pumping lemma. Task: Be $\sum { =\left\{ a,b,c \right\} } $ and $S=\left\{ bx{ c }^{ m }|x\in { \left\{ a,b \...
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1answer
61 views

How to prove a language is not regular using the Pumping Lemma?

I need some help with my proof, because I'm not sure if the following works. Tips and Tricks are welcome since this topic is completely new to me and very difficult. Task: Prove that $M = \left\{ a^...
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1answer
59 views

picking a word for pumping lemma for L = {a^n b^m c^n b^m a^n | m,n≥0}

If i have a language like $L = \{a^n b^m c^n b^m a^n \mid m,n\ge0\}$ when i pick a word for the language, would it be correct if i pick any of these words: $w = a^k c^k$, $w = a^k b^m c^k $, $w = b^...
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1answer
142 views

Language that fulfills pumping lemma but is not in RE

I am supposed to find a language $$L\subseteq \Sigma ^*, \Sigma \subseteq \mathbb{N}$$ that fullfills the pumping lemma and is not in RE and not in coRE. I've never constructed a language with a given ...
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Is this language context-free? $\Sigma$ = {a,b,#} L = {x1#x2#…#xk : k$\geq$2, every $x_i \in$ {a,b}* and xi $\neq$ xj for every pair i $\neq$ j} [duplicate]

Is this language context-free? $\Sigma$ = {a,b,#}, L = {x1#x2#...#xk : k$\geq$2, every $x_i \in$ {a,b}* and xi $\neq$ xj for every pair i $\neq$ j} I think it is not, because the PDA can't memorize ...
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0answers
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contextfree? {w1w2 | w1,w2 $\in$ {a,b}* $\land$ |w1| = |w2| $\land$ w1 $\neq$ w2} [duplicate]

Is this language contextfree? {w1w2 | w1,w2 $\in$ {a,b}* $\land$ |w1| = |w2| $\land$ w1 $\neq$ w2}. I think it's not but can't prove it.
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3answers
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Prove a^4n b^m is irregular using puming lemma

My assignment is to prove that the language $L = \{ a^{4n} b^m \mid n > m >= 0\}$ is not a regular language. My first attempt was to prove that if if you set $a^l$ and $b^{l-1}$ you'd have an ...
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1answer
31 views

What is the minimum pumping length of the union of two languages?

If I have two languages L1 and L2 that are pumpable, what is the minimum pumping length for the union of them? Does it differ if either of them contains just one string like 001?
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2answers
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Prove or disprove L is regular

There is question in one of my exercise but I couldn't prove or disprove anything about it. This is language $L$ which is introduced with grammar: $$S \to 0S1 | 1S0 | AA$$ $$A \to 0A | \lambda|A1$$ ...
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Justification for the pumping lemma of context free languages

I understand intuitively why the pumping lemma for regular languages must hold. That is to recognize a infinite string with a finite amount of states you must repeat states and you can "pump" those ...
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Several simple propositions about regular languages

(Originally posted on Math-Stackexchange) https://math.stackexchange.com/questions/2982949/regular-languages-and-regular-expressions Notation: $\Sigma:=\{a_1,\cdots ,a_\Delta\}$ finite alphabet $\...
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1answer
71 views

Using pumping lemma to prove $L2 = \{a^ib^j |i > j \}$ non-regular

I'm having issues using the pumping lemma to prove $L2 = \{a^ib^j |i > j \}$ is non-regular. It's obvious to know that the language is non-regular as there is no way of tracking $a^{i's}$ and $b^{...
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1answer
58 views

How to show that the language made up of strings with nlogn 0s is not regular with the pumping lemma?

How to show that the following language is not regular with the pumping lemma? $$L=\left\{0^{n\lceil\log_2 n\rceil} \,\middle|\, n\in \mathbb{N}-\{0\}\right\}.$$
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1answer
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Proving a language is non-regular using the Pumping Lemma for non-binary strings [duplicate]

I am unsure of how to prove this language is non-regular. I do not even know where to start to develop a string that would prove the language is non-regular by contradiction. Any help would be ...
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1answer
106 views

Proving $L = \{a^nb^m \mid n, m≥0, n \neq m\}$ is not regular by use of Pumping Lemma

I've been struggling with this problem for quite a while now and every explanation I have managed to find doesn't seem to correctly solve it. Question Proving $L = \{a^nb^m \mid n, m≥0, n \neq m\}$...
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1answer
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Pumping Lemma Question: About the cases for y in the xy^iz criterion

Problem statement: Let $\Sigma = \{a, b, c\}$, and consider the task of multiplication encoded in the language $L = \{a^n b^k c^{nk} : n \geq 0, k \geq 0\}$. Prove that L is not regular using the ...
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1answer
126 views

Undecidable problem intersection of two DCFL languages is DCFL?

We have two deterministic pushdown automatas A and B, which languages are deterministic context-free. The problem is to decide if there exists a deterministic pushdown automata, which language is an ...
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1answer
41 views

Is my pumping lemma proof correct? [duplicate]

Show that $L = \{a^nb^l \ | \ n \leq l \}$ is not regular I'd like to check if my proof for this is correct. Proof: Choose any positive integer $m$. Pick $w = a^mb^{m+1} \in L$. Note that $|w| = 2m+...
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1answer
46 views

Use the pumping lemma to prove that the following language is not context free

Can anyone help with the following problem ? Let $B = \{ a^{n}b^{m}c^{m}d^{2n} | n,m ≥ 0 \}$, use the pumping lemma to prove B is not context-free Thanks in advance.
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3answers
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is this language regular and why pumping lemma doesn't work?

I was told that this language is regular but as I can show below, pumping lemma is not working for it. What am I doing wrong? Is this language really regular? Why?
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1answer
40 views

Proving irregularity of $\{a^nb^k \mid n > k \text{ or } n \neq k-1\}$

I need help with proving the following language is not regular: $$ L = \{ a^n b^k \mid n > k \} \cup \{ a^n b^k \mid n \neq k-1 \} $$ My usual methods using pumping lemma are not getting me ...
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1answer
134 views

Can we prove using pumping lemma that language F = {$a^ i b ^j c ^k$ | i, j, k ≥ 0 and if i = 1 then j = k} is not regular?

I am currently solving a problem in which we have to show that we can not prove using pumping lemma that the language mentioned in the question is not regular.Here is the full question Consider the ...
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3answers
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How to prove using pumping lemma that language generated by a(b*)c(d*)e is regular?

I am studying pumping lemma from Introduction to theory of computation by Michael Sipser. I wanted to check if the language generated by regular expression ...
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1answer
73 views

Prove {0^n OR 1^2n OR 2^3n | n >= 0} is not context free

How to prove using pumping lemma {0^n OR 1^2n OR 2^3n | n >= 0} is not context free This isnt the same language as {0^n1^2n2^3n | n >= 0} as this language the numbers need to be in order.
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1answer
45 views

Prove that $L^r$ is context free without alphabet

I'm stuck with this problem: Given $L$ a CFL on the alphabet $\Sigma$. Prove that $L^r=\{x^r|x\in L\}$, where for each $a\in\Sigma$ and $y\in\Sigma^*$, $$\epsilon^r=\epsilon,$$ $$(ay)^r=y^ra,$$ is ...
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3answers
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Why does the Pumping-lemma for context-free languages use uvwxy, but the one for regular ones uvw?

Basically what the title says. Why can you "ignore" the "xy" part if you want to prove whether a language is regular?
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1answer
75 views

General version of pumping lemma for regular languages, how many partitions to consider

The pumping lemma for regular languages states, that one should consider a string $w = xyz, w\in L$, that is, every possible division of $w$ into $xyz$. The article on wikipedia says, that this ...
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0answers
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Proving a language is not context-free using the pumping lemma

I had a question regarding the use of the pumping lemma for a particular language I came across. I feel like I have almost solved it, but have gotten stuck on the last steps and wanted some advice. ...
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1answer
69 views

Why is $L := \{b^2a^nb^ma^3|m,n \geq 0\}$ a regular language?

(Pre-note: I'm learning Theory of Computation on my own, so bear with me if I'm saying something wrong/stupid.) Why is $L := \{b^2a^nb^ma^3\mid m,n \geq 0\}$ a regular language? This question ...
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1answer
89 views

I can construct DFA for $a^{3n+1}$ but pumping lemma says it is not regular

Recently I stumbled across this language $L=\{a^{n}a^{{(n + 1)}^2-n^2} \in \Sigma^* \mid n\geq 0\}$ that I can rewrite as $a^{3n + 1}$. So I applied the pumping lemma to see if it is non regular, ...
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1answer
76 views

Which word to pump in pumping lemma?

Let say we have a Language $L = \{0^m1^n \mid m,n \geq 0 \land m \neq n \}$. If I want to use the pumping lemma to disprove that the language is regular or context-free, how do I choose the word in ...
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2answers
133 views

Pumping lemma: the set of strings of 0s and 1s such that when interpreted as an integer, that integer is prime

In the section of my textbook covering the pumping lemma, there are practice questions asking us to prove a given language is not regular. I have not been able to solve this one: The set of ...
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0answers
75 views

Is $\{ a^i b^j c^k : i + 1000\ < j + 100 < k \}$ context-free?

I have this language: $$ L = \{ a^i b^j c^k : i + 1000\ < j + 100 < k \}, $$ and what I believe is that we can't prove with the Pumping Lemma that it is not context-free, because we would ...
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0answers
13 views

How do we determine p (pumping length) in pumping lemma for CFL? [duplicate]

This has been confusing me for a while, how do we exactly choose the pumping length when we want to prove whether a language is CFL or not. For example, when we want to prove that {ww, w: {0,1}* } why ...
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1answer
32 views

Proving that language is regular or not [duplicate]

How to prove that the language over the alphabet $\{0, 1, +, =\}$ is regular or not: $\{a+b=c:a,b,c \text{ are integers in binary for which } a \text{ plus } b\text{ equals } c\}$ I started with the ...