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Hmmm. It can't be done with boolean algebra that's for sure, but I could wire one up physically. The trick is wiring one of the inputs to a power lead of another.

        I1           I2
        |            |
      /-+-\          |
      |   |          |
     \|   |/         |
     |\   / |        |
.|---| \ /  |---|>   |
     \  V  /         |
      \   /          |
       \ /           |
        V            |
        |            |
      /-+-\          |
      |   |          |
     \|   |/         |
     |\   / |        |
.|---| \ /  |--------/
     \  V  /
      \   /
       \ /
        V 
        |
        |
     AND OUTPUT

Both XOR gates are wired up as NOT gates. The trick involved is that if you wire VCC to GND (or by extension a logic ground), the output is a weak GND.

Disclaimer: this works on the silicon I have, but might not work on all silicon.