Hmmm. It can't be done with boolean algebra that's for sure, but I could wire one up physically. The trick is wiring one of the inputs to a power lead of another.
I1 I2 | | /-+-\ | | | | \| |/ | |\ / | | .|---| \ / |---|> | \ V / | \ / | \ / | V | | | /-+-\ | | | | \| |/ | |\ / | | .|---| \ / |--------/ \ V / \ / \ / V | | AND OUTPUT
Both XOR gates are wired up as NOT gates. The trick involved is that if you wire VCC to GND (or by extension a logic ground), the output is a weak GND.
Disclaimer: this works on the silicon I have, but might not work on all silicon.