Can you explain how does this expression follow the grammar of lambda calculus?
λx.x((λy.yy)x)x = λx.x(xx)x
I am not sure why we have the parentheses following the .x
(on both sides of the equation).
Can you explain how does this expression follow the grammar of lambda calculus?
λx.x((λy.yy)x)x = λx.x(xx)x
I am not sure why we have the parentheses following the .x
(on both sides of the equation).