Hmmm. It can't be done with boolean algebra that's for sure, but I could wire one up physically. The trick is wiring one of the inputs to a power lead of another.

            I1           I2
            |            |
          /-+-\          |
          |   |          |
         \|   |/         |
         |\   / |        |
    .|---| \ /  |---|>   |
         \  V  /         |
          \   /          |
           \ /           |
            V            |
            |            |
          /-+-\          |
          |   |          |
         \|   |/         |
         |\   / |        |
    .|---| \ /  |--------/
         \  V  /
          \   /
           \ /
            V 
            |
            |
         AND OUTPUT

Both XOR gates are wired up as NOT gates. The trick involved is that if you wire VCC to GND (or by extension a logic ground), the output is a weak GND.

Disclaimer: this works on the silicon I have, but might not work on all silicon.