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A clique is a subset of the vertices of a graph such that every pair of vertices in the subset is connected by an edge.

3 votes
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Implementing Nesetril and Poljak's clique detection algorithm

The high-level idea is this: the existence of a triangle in $H$ corresponds to the existence of a clique of size $3\ell$ in $G$, and we know how to detect triangles using matrix multiplication. …
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4 votes
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Can I find a clique with more than 2 nodes in a bipartite graph?

A clique of size at least 3 contains a triangle, and a triangle $K_3$ clearly cannot be colored with 2 colors. …
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2 votes
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Applications of the splittance of a graph/ Turning graphs into splitgraphs

There is nothing deeper to it than what you describe: if the graph is split or it has "small" distance to being split (e.g., you can make it split by removing a small number of edges/vertices), you mi …
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2 votes
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Understanding CLIQUE structure

So assume $G$ contains a clique of size $k$, and you have a proper coloring with less than $k$ colors. It follows that the clique contains at least two vertices with the same color. … Further, one might also wonder if the chromatic number of a graph would always equal the clique number. …
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3 votes
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Algorithm to compute partitions of a graph in N cliques

This problem is known as clique cover and it's NP-complete. In other words, no efficient algorithm is known. …
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5 votes
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The equivalence relations cover problem (in graph theory)

It is upper bounded by the clique covering number (the minimum collection of cliques such that each edge of the graph is in at least one clique). …
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3 votes

Maximal cliques in a multipartite graph - efficient?

A maximal clique and a maximum clique are in general different. … A set of vertices $S$ is a maximal clique if $S$ is a clique and you cannot add any vertex to $S$ such that the resulting set would form a clique. …
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2 votes

Clique-problem for planar graph

So suppose the problem is "is there a clique of size $k$ in a given planar graph $G$?" Now, if $k \geq 5$, we immediately answer NO. … If any one of them induces a $k$-clique, we answer YES. Otherwise, we answer NO. Hence, the problem is in P. …
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