Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 755

For questions about method for storing and manipulating numbers on computer systems, such as floating point or binary representations.

4 votes

"Compressing" rationals given error bounds

Continued fractions are an efficient way to enumerate rational numbers that are a good approximation of your number $x$. In particular, given a real number $x$, you can generate a sequence of truncat …
D.W.'s user avatar
  • 166k
3 votes
Accepted

What is the 1's and 2's complement of 0.01101?

One's and two's complement apply to (fixed-point) encodings of integers. They don't apply to floating-point numbers. Floating point is different.
D.W.'s user avatar
  • 166k
2 votes

Space-efficient representation of potentially very large arbitrary-precision rationals?

Representing a rational number as ${a \over b} \times c^d$ where $a,b,c,d$ are integers can represent all three classes of numbers you mentioned efficiently. You can do standard operations on numbers …
D.W.'s user avatar
  • 166k
2 votes

Why does little endian apply to numbers and not to text strings?

You certainly could do it that way. It's an arbitrary decision. You could store characters in ascending order, or in descending order.
D.W.'s user avatar
  • 166k
2 votes

Is there any practical trick to mentally count in Gray code?

Wikipedia describes a very simple algorithm for this task: To construct the binary-reflected Gray code iteratively, at step 0 start with the $\text{code}_0 = 0$, and at step $i > 0 $ find the bit pos …
D.W.'s user avatar
  • 166k