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Calculating $\sum_{i=1}^a \lfloor a/i \rfloor i^2$

I have a sum: $$S = \sum_{i=1}^n{\lfloor a/i \rfloor i^2},$$ where $a$ is a constant. Is there a way to speed this up? That is, can we avoid iterating overl all $i$s, possibly calculating it in logar …
Robert Hanigan's user avatar