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Questions about the binary search algorithm, which can be used to find elements of an ordered list in O(log n) time.
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Why is binary search faster than ternary search?
If you apply binary search, you have $$\log_2(n)+O(1)$$ many comparisons. If you apply ternary search, you have $$ 2 \cdot \log_3(n) + O(1)$$ many comparisons, as in each step, you need to perform 2 c …