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Let $A$ and $O$ be the events apple and orange (fruit). Let $R$ and $S$ be the events red and sphere. By Bayes' law, $$\Pr[A | R \wedge S] = \frac{ \Pr[R \wedge S | A] \Pr[A] }{ \Pr[R \wedge S] };$$ …
answered Jun 27 '18 by Solomonoff's Secret