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Questiont about issues of concurrency such as synchronization and deadlocks.

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While checking for conflict serializable schedules, we should be sure to avoid RW, WW, WR conflicts. Also the relative order of operations internal to each transaction also needs to be maintained. For …
answered Jan 21 '18 by virmis_007
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The resulting precedence graph for your example will contain a cycle due to $R1(A) W2(A) R1(A)$. Hence its not conflict serializable. Since one example is sufficient to disprove the statement, therefo …
answered Jan 21 '18 by virmis_007
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First of all let's permute everything; all operations of every transaction. Doing this will result in $(m_1 + m_2 + m_3 + ... + m_k)!$ Now since we cannot change the relative order of execution of op …
answered Jan 21 '18 by virmis_007