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here the first grammar given is : S → AA|SBBa|b A → ABa|BS|a B → BBb|a|λ first, remove epsilon productions:(B → λ): S → AA|SBBa|SBa|Sa|b A → ABa|BS|a|Aa|S B → BBb|a|Bb|b second, remove Unit productions and some unreachables may create: S → AA|SBBa|SBa|Sa|b A → ABa|BS|Aa|AA|SBBa|SBa|Sa|a|b B → BBb|Bb|a|b Then we are ready for CNF in two step furtuere: 1) S → ...


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Look at the Swift language where the available operators are not defined in the language, but in the standard library. There are rules that let the compiler distinguish between binary and unary operators. An expression is operands, possibly preceded or followed by unary operators, and separated by binary operators. That’s decided by the grammar, without any ...


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