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If there are only three possible values, all possible Huffman codes have symbol lengths 1, 2, 2. One value has a 1 bit symbol which is 0 or 1, that’s 6 choices. Then we know the two possible 2 but symbols; one of the remaining two values uses one code, and the other value uses the other. 2 more choices, so a total of 12 choices.


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Yes, that is a reasonable architecture. You could use any architecture for processing images, and have it output a representation of the image (take any classification architecture, and remove the last layer). You could also use any architecture for text, and have it output a representation of the text. Finally, for other inputs, you could use a fully ...


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