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assume address printed out to be a "byte address" guess whether the offset to find is addressable unit in page or byte in page if addressable unit in page, figure out its size with nothing more than 64-bit to go on a first assumption is 8 bytes guess the representation wanted for virtual page number & offset (Base conversions in the process ...


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Let's call the memory address $x$. Thus $x$ is composed of bits $x_0,\ldots,x_{31}$, where $x_0$ is the LSB and $x_{31}$ is the MSB. A memory address belongs to the EEPROM mapped area if it is in the range $0,\ldots,2^{20}-1$. You can check that this is equivalent to the condition $x_{20} = \cdots = x_{31} = 0$, which you can translate into a Boolean ...


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