New answers tagged union-find
2
If you combine union by rank or union by size with e.g. path compression the amortized complexity is the same [$O(m\alpha(m,n))$]. But notice that Wikipedia uses union by rank in order to prove the upper bound $O(m\log^*(n))$ because for proof purposes the union by rank algorithm is simpler to handle. On the other hand if you are implementing such a data ...
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