Kyle Jones
• Member for 9 years, 10 months
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• Seattle, WA

I read a survey paper a few years ago that seems relevant, "Successful SAT Encoding Techniques" by Magnus Björk. Abstract: This article identifies good practices for SAT encodings by ...

As mentioned in a comment, any method of determining satisfiability of a Boolean formula can be easily converted into a method for finding the satisfying variable assignment. This is because Boolean ...

Yes, each input value is weighted before being fed into the nodes in the next layer. Each input/output pair of "neurons" has its own weight and it is these weights that are adjusted by the neural ...

The simplification you're describing is called subsumption. It's a standard technique and some SAT solvers (e.g. minisat) will apply it along with other simplification techniques as a preprocessing ...

The final constraint you need to encode is that $k$ or fewer variables in the set ${x_1, x_2, ..., x_n}$ is set true. There is a good reference question that outlines several methods for encoding a 1-...

This $\qquad \forall x \exists z \space (x = z)$ is a true QBF. Whatever Boolean value $x$ is set to, $z$ can be set to match. Translated to quantified CNF: $\qquad \forall x \exists z \space (x \... View answer 4 votes Yes. The quantifiers can be ignored for the sake of the test since a quantified Horn formula is syntactically identical to an unquantified one except for the quantifiers. That is, a quantified Horn ... View answer Accepted answer 13 votes A comment mentions a reduction from X3C to SUBSET PRODUCT attributed to Yao. Given the target of the reduction it wasn't hard to guess what the reduction was likely to have been. Definitions: EXACT ... View answer Accepted answer 19 votes There are at least four such$NP$-complete problems listed in the appendix of Garey and Johnson's COMPUTERS AND INTRACTABILITY: A Guide to the Theory of NP-Completeness. [AN6] NON-DIVISIBILITY OF A ... View answer 5 votes An unquantified CNF formula consisting of clauses containing a single positive literal plus any number of negated literals is always satisfiable. To produce a satisfying assignment, you simply set ... View answer Accepted answer 12 votes The confusion arises from a misunderstanding of what being polynomial in the size of the largest instance means. It does not mean that polynomial growth of the compressor's output is allowed as the ... View answer Accepted answer 7 votes It can be, but the solution process is equivalent to converting a CNF formula to DNF, which is NP-hard. You will at worst end up exploring an exponential number of disjunction branches. View answer 1 votes If, as I suspect, you are still trying to convert quantified 3-CNF formulas into quantified mixed Horn formulas, the answer is that quantifiers for the newly added bridge variables can be placed ... View answer Accepted answer 1 votes Use a SAT solver that also allows you to express pseudo-Boolean constraints. Encoding the verification of the existence of the tiling of an NxN grid as a CNF formula is straightforward. Each grid ... View answer Accepted answer 5 votes Adding permutations isn't about preventing slow servers from becoming bottlenecks, rather it's about dispersing a convoy once one forms behind a slow server. Because of the way tract locations are ... View answer 6 votes The proof is not correct. As you've indicated the reduction needs to go in the other direction, i.e. integer programming must be reduced to their problem, not the other way around. View answer 2 votes You seem to be trying to describe and use the resolution proof system. Two points: The resolution rule is only applied to two clauses at a time. The resulting clause, the resolvent, can be added to ... View answer 7 votes (1) is hard to answer unless you clarify what you mean by "versions of SAT problem." If we limit ourselves to the classes listed in Schaefer's "The Complexity of Satisfiability Problems", the only ... View answer Accepted answer 4 votes In the papers I've read the time complexity of DPLL is expressed in terms of the number of variables in the CNF formula. Using the number of clauses is inappropriate in general because it is known ... View answer 14 votes For the special case of k out of n variables true where k = 1, there is commander variable encoding as described in Efficient CNF Encoding for Selecting 1 to N Objects by Klieber and Kwon. Simplified:... View answer 3 votes Your problem is the same one faced by SAT solvers who want to eliminate subsumed clauses from a CNF formula. Any clause$B$that contains a superset of the literals of another clause$A$in the ... View answer 1 votes Apple has just proudly stated that their new mac pro will be able to give up to 7 teraflops of computing power. Flops stands for Floating Point Operations Per Second. How exactly is this benchmarked ... View answer 1 votes If the four Coffman conditions exist, you have an existing deadlock. The circular wait condition guarantees at least two blocked processes exist, each waiting for a resource held by the other. The ... View answer Accepted answer 6 votes Finding a stable argument set is equivalent to finding an independent set in the directed graph of argument attacks, with the added restriction that some member of the set must be adjacent to each ... View answer 15 votes Unless you're translating mathematical problems to SAT instances as a learning exercise, your time will be much more fruitfully spent learning about satisfiability modulo theories. SMT will allow you ... View answer 5 votes What you are describing is unrelated to alpha-beta pruning. The tendency of fixed-depth minimax searches to badly underestimate or overestimate positional scores in dynamic situations is known as the ... View answer 3 votes 1... On line 33 why is node.lowlink = min(node.lowlink, n.index) — shouldn't it be same as line 31: node.lowlink = min(node.lowlink, n.lowlink)? The code works either way. The two possibilities are: ... View answer 1 votes Is OPT = m? is a coNP decision problem. A "no" answer has a certificate verifiable in polynomial time, the certificate being a valid bin packing that uses fewer than$m\$ bins. The same is true for ...