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Results tagged with tcp
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user 152079
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TCP Warp Around time - Sequence number Problem
Consider a long-lived TCP session with an end-to-end bandwidth of 1Gbps. The session starts with a sequence number of 1234. … The solution given for above question was : [(2^32)*8]/(10^9) = 34.3597 sec
But what I think it should be : [(2^32)208]/(10^9) = 687.194 sec
I have multiplied it by 20 because minimum size of TCP packet …
