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is the string aabb in the language of this Turing machine ?? as upon reading aa it goes to the final state but upon b there is no transition defined so won't it result in a dead configuration?

Let $A$ and $B$ be finite alphabets and let $\#$ be a symbol outside both $A$ and $B$. Let $f$ be a total function from $A^∗$ to $B^∗$. We say $f$ is computable if there exists a Turing machine $M$ wh …

$L = \{ \langle M \rangle \mid M \text{ accepts two strings of different lengths} \}$. What is complement of this language? my attempt: the complement is: $M$ accepts no two strings of same lengt …

$L_1=\{ ⟨M⟩ ∣M$ takes at least 2016 steps on some input$\}$ the answer says $L_1$ is recursive. I am stuck at one point and i am wasting my time on it here for $L_1$ if we are given a set of to see …

what is meant by EFFECTIVE ENUMERATION i have comes across this word when I was reading about enumerators for Turing machines is it same as LEXICOGRAPHIC ORDER? so effective enumeration is possible f …

Define languages L0 and L1 as follows : L0={⟨M,w,0⟩∣M halts on w} L1={⟨M,w,1⟩∣M does not halt on w} Here ⟨M,w,i⟩is a triplet, whose first component M is an encoding of a Turing Machine, second …