Take any time complexity class and its corresponding nondeterministic counterpart: $\mathsf{DTime(F)}$ and $\mathsf{NTime}(F)$ where $F$ is a family of nice functions containing polynomials and bounded by exponential functions. You are asking if we know these two classes are equal. We don't know!
Take $SAT$ as an example. A certificate can be verified in linear time so it is in $\mathsf{NTime}(n)$. However there is no algorithm that solves even very simple instances of $SAT$ (e.g. decide if the propositional statement that n+1 pigeons can be mapped into n holes is false) significantly faster than brute-force, i.e. exponential time. In other words, we don't even know if $\mathsf{NTime}(n) \subseteq \mathsf{DTime}(f)$ where $f$ is a little bit smaller than exponential function $2^n$. IF what you are asking was true then the lhs would be subset of your $\mathsf{NTime}(F)$ and therefore by your assumption a subset of $\mathsf{DTime}(F)$ where $F$ is smaller than exponential functions.
The question about $\mathsf{P}$ and $\mathsf{NP}$ is not only important because of Cobham's thesis that efficient computations are captured by $\mathsf{P}$, we don't know any simulation of nondeterminisitic time bounded machines by deterministic ones which doesn't use brute force search for the certificate. So the essential question about $\mathsf{P}$ vs. $\mathsf{NP}$ is can we find a certificate in a space exponentially faster than brute-force search of the space?
In fact, the question was known in Russian literature as the perebor problem (the brute-force search problem).
If you don't accept Cobham's thesis then you can think of $\mathsf{P}$ vs. $\mathsf{NP}$ question as the flagship of questions about the relation between verifying and constructing answers, or as I said above, as the question about existence of deterministic search algorithms which are exponentially faster than brute-force search.