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Questions about problems which cannot be solved by any Turing machine.
2
votes
Can the complement of a non-recursive language be RE
From your question I believe there is some confusion of the terms being used here. A recognizable language L is one such that a turing machine exists accepting it, halting on every yes instance. Ther …
2
votes
Mapping reduction to show NeverHalt is undecidable
You will not prove that $NeverHalt_{TM}$ is undecidable by "finding a TM whose language will "help" us solve" it. This would actually prove the opposite, if $M$ is a TM deciding some language.
You h …