New answers tagged counting
2
There is a trick to achieve this. Basically you always keep the subset you are currently considering sorted.
subset = [];
function forSubsets(n,k,m=1){
if(subset.length == k) console.log(subset);
else{
for(var i = m; i <= n; i++){
subset.push(i);
forSubsets(n,k,i);
subset.pop();
}
}
}
As you can see on each recursion one ...
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